How do you solve the system of equations 7x−2y=−33 and 5x+4y=9 by elimination?

1 Answer
Nallasivam V
Mar 22, 2017

x=−3
y=6

Explanation:

7x−2y=−33 -----------------------(1)
5x+4y=9 ------------------------(2)

Multiply equation (1) with 2

7x−2y=−33 -----------------------(1) ×2

14x−4y=−66 ----------------------(3)
5x+4y=9 ------------------------(2) ---(3)+(2)
19x=−57
x=−5719=−3

x=−3

Substitute x=−3 in equation (1)

7(−3)−2y=−33
−21−2y=−33
−2y=−33+21=−12
y=−12−2=6
y=6

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