How do you solve the system of equations #8x + 3y = 93# and #4x + 3y = 69#?

1 Answer
Jan 12, 2018

#(x,y)=(6,15)#

Explanation:

Given
[1]#color(white)("XXX")8x+3y=93#
[2]#color(white)("XXX")4x+3y=69#

after subtracting [2] from [1]
[3]#color(white)("XXX")4x=24#

then dividing both sides of [3] by #4#
[4]#color(white)("XXX")x=6#

Now substitute #6# for #x# in one of the original equations (I choose [2])
[5]#color(white)("XXX")4xx6 + 3y =69#

subtract #4xx6=24# from both sides of [5]
[6]#color(white)("XXX")3y=45#

divide both sides of [6] by #3#
[7]#color(white)("XXX")y=15#