How do you solve the system of equations $8y - 5x = 79$ and $5y = 4x + 45$ ?

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Answer 1 · 2018-05-06T23:11:14

The answer $y=13$
$x=5$

show below

$8y - 5x = 79$ ........(1)

$5y = 4x + 45$ ............(2)

hit the (2) by 8

$5(8y)=32x+360$ .....(3)

rewrite (1) in the form

$8y=79+5x$ ......(4)

now put 4 in 3

$5(79+5x)=32x+360$

$395+25x=32x+360$

$7x=35$

$x=5$

$8y=79+25$

$8y=104$

$y=13$

How do you solve the system of equations 8y - 5x = 798y - 5x = 79 and 5y = 4x + 455y = 4x + 45?