How do you solve the system of equations #-9x - 2y = - 3# and #36x + 8y = 13#?

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Answer 1 · 2018-04-21T18:54:40

See a solution process below:

First, we can multiply the first equation by #color(red)(-4)# giving:

#color(red)(-4)(-9x - 2y ) = color(red)(-4) xx -3#

#(color(red)(-4) xx -9x) - (color(red)(-4) xx 2y ) = 12#

#36x - (-8y) = 12#

#36x + 8y = 12#

Because the left side of both equations are the same but the right sides are different, this indicates there is no solution to this problem.

Or, the solution is the null or empty set: #{O/}#

This means both lines are parallel but not the same line.