How do you solve the system of equations $9x + 3y = - 18$ and $3x - 5y = - 24$ ?

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Answer 1 · 2018-03-27T19:08:06

x=-3
y=3

= $9x+3y=-18$
Divide 3 on both sides

= $3x+y=-6$

Now Subtracting

= $(3x+y=-6)-(3x-5y=-24)$

= $6y=18$

** = $y=3$ **

For $x$ doing putting in following

= $3x-5y=-24$

= $3x-5(3)=-24$

= $3x=-9$

** = $x=-3$ **

How do you solve the system of equations 9x + 3y = - 189x + 3y = - 18 and 3x - 5y = - 243x - 5y = - 24?