How do you solve the system of equations $a+ 5b = 1$ and $2a = - 10b + 2$ ?

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Answer 1 · 2018-07-16T12:20:48

$-5b+1,b$ where $b$ is a real number

Dividing the second equation by $2$ we get

$a=-5b+1$

this is the same equation like the first one,
So we get all Solutions as

$-5b+1,b$
where $b$ is a real number

How do you solve the system of equations a+ 5b = 1a+ 5b = 1 and 2a = - 10b + 22a = - 10b + 2?