How do you solve the system of equations C-4r=-3 and 2C-8r=-6?
1 Answer
The lines are the same, so there is an
Explanation:
2C - 8r = - 6
You can give the equations the same coefficient for C by multiplying the first equation by 2.
After you do that, this is the system of equations:
2C - 8r = - 6
2C - 8r = - 6
In other words, both equations are for the same line.
When you are graphing systems of equations, there are a few kinds of systems:
- The lines may intersect at exactly one point.
That point is"the solution" to the system.
- If the lines are parallel, they never intersect.
So there are"no solutions" to that system.
- The lines are the same line.
They intersect at every point, so there are an"infinite number" of solutions.
http://www.montereyinstitute.org/courses/DevelopmentalMath/COURSE_TEXT2_RESOURCE/U14_L1_T1_text_final.html
Here's a web site where you can find out more about systems of equations:
http://www.montereyinstitute.org/courses/DevelopmentalMath/COURSE_TEXT2_RESOURCE/U14_L1_T1_text_final.html