How do you solve the system of equations graphing #y=-3, 2x=8#?
1 Answer
Dec 20, 2017
Explanation:
#y=-3#
#"is a horizontal line parallel to the x-axis and passing "#
#"through all points in the plane with a y-coordinate of - 3"#
#2x=8rArrx=4#
#"is a vertical line parallel to the y-axis and passing"#
#"through all points in the plane with an x-coordinate of 4"#
#"the point of intersection "=(4,-3)#
graph{(y-0.001x+3)(y-1000x+4000)((x-4)^2+(y+3)^2-0.04)=0 [-10, 10, -5, 5]}
