How do you solve the system of equations #x= 2y + 6# and #3x + 2y = 10#?

Question

2808 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-16T04:34:43

#x=4#
#y=-1#

Given -

#x=2y+6# ---------------------(1)

#3x+2y=10# ------------------(2)

The value of #x# in terms of #y# is given in equation (1)

Substitute #x=2y+6# in equation (2)

#3(2y+6)+2y=10#

By doing this you have replaced variable #x#. Now you have #y# variable only.

#6y+18+2y=10#

#8y=10-18#

#y=(-8)/8=-1#

#y=-1#

Substitute #y=-1# in equation (1)

#x=2(-1)+6#
#x=-2+6#
#x=4#