How do you solve the system of equations #-x+4y=3# and #x+2y=5#?

1 Answer
Jul 29, 2016

#x=7/3#
#y=4/3#

Explanation:

#-x+4y=3#
#x+2y=5#
Adding up the above 2 equations
we get
#-x+4y+x+2y=3+5#
or
#-x+x+4y+2y=8#
or
#0+6y=8#
or
#6y=8#
or
#y=8/6#
or
#y=4/3#=======Ans #1#
From the equation #-x+4y=3#
we get
#x+3=4y#
or
#x+3=((4)(4))/3#
or
#x+3=16/3#
or
#x=16/3-3#
or
#x=(16-9)/3#
or
#x=7/3#=========Ans #2#