How do you solve the system of equations #-x + 8= y# and #- 2x + 3y = 64#?

1 Answer
Jim G.
Jun 13, 2018

#x,y)to(-8,16)#

Explanation:

#-x+8=yto(1)#

#-2x+3y=64to(2)#

#"substitute "y=-x+8" into equation "(2)#

#-2x+3(-x+8)=64#

#-2x-3x+24=64#

#-5x+24=64#

#"subtract 24 from both sides"#

#-5x=64-24=40#

#"divide both sides by "-5#

#x=40/(-5)=-8#

#"substitute "x=-8" into equation "(1)" for y"#

#y=-(-8)+8=16#

#"point of intersection "=(-8,16)#

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