How do you solve the system of equations -x + 8= y−x+8=y and - 2x + 3y = 64−2x+3y=64?

1 Answer
Jim G.
Jun 13, 2018

x,y)to(-8,16)x,y)→(−8,16)

Explanation:

-x+8=yto(1)−x+8=y→(1)

-2x+3y=64to(2)−2x+3y=64→(2)

"substitute "y=-x+8" into equation "(2)substitute y=−x+8 into equation (2)

-2x+3(-x+8)=64−2x+3(−x+8)=64

-2x-3x+24=64−2x−3x+24=64

-5x+24=64−5x+24=64

"subtract 24 from both sides"subtract 24 from both sides

-5x=64-24=40−5x=64−24=40

"divide both sides by "-5divide both sides by −5

x=40/(-5)=-8x=40−5=−8

"substitute "x=-8" into equation "(1)" for y"substitute x=−8 into equation (1) for y

y=-(-8)+8=16y=−(−8)+8=16

"point of intersection "=(-8,16)point of intersection =(−8,16)

Related questions
Impact of this question
892 views around the world
You can reuse this answer
Creative Commons License