How do you solve the system of equations #y=11x-6# and #y=-6x+11# by graphing?

1 Answer
Jan 10, 2018

See a solution process below:

Explanation:

Graph Equation 1:

First, find two points to solve the first equation, plot the points and draw a straight line through the points:

For #x = 0#
#y = (11 * 0) - 6#
#y = 0 - 6#
#y = -6# or #(0, -6)#

For #x = 1#
#y = (11 * 1) - 6#
#y = 11 - 6#
#y = 5# or #(1, 5)#

graph{(y - 11x + 6)(x^2+(y+6)^2-0.1)((x-1)^2+(y-5)^2-0.1)=0 [-25, 25, -12.5, 12.5]}

Graph Equation 2:

First, find two points to solve the second equation, plot the points and draw a straight line through the points:

For #x = 0#
#y = (-6 * 0) + 11#
#y = 0 + 11#
#y = 11# or #(0, 11)#

For #x = 2#
#y = (-6 * 2) + 11#
#y = -12 + 11#
#y = -1# or #(2, -1)#

graph{(y+6x-11)(y - 11x + 6)(x^2+(y-11)^2-0.2)((x-2)^2+(y+1)^2-0.2)=0 [-30, 30, -15, 15]}

The Solution Is:

graph{(y+6x-11)(y - 11x + 6)((x-1)^2+(y-5)^2-0.05)=0 [-2, 22, -2, 10]}

#(1, 5)#