How do you solve the system of equations #y= 2x - 7# and #x = 3y + 11#?

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Answer 1 · 2017-06-17T13:02:08

#x=-2#
#y=-11#

The first equation gives us a value for #y# that we can substitute for #y# in the second equation:

#x=3(2x-7)+11#

#x=6x-21+11#

#x=6x-10#

Rearranging:

#5x=-10#

#x=-2#

We can now substitute this back into first equation to find the value of #y#:

#y=2(-2)-7=-11#