How do you solve the system of equations #y=3x-2# and #y=-x+2# using substitution?

1 Answer
jags
Jun 27, 2016

#x = 3/4 and y = 5/4#

Explanation:

Given:

#y = 3x - 1# - > Equation 1
#y = -x + 2# - > Equation 2

Substituting value of y in 1, we get #(-x + 2) = (3x -1) => (2 + 1) = (3x + x) = > 4x = 3 => x = 3/4#

Substituting value of x in Equation 2, we get

#y = -3/4 + 2 => y = 5/4#

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