How do you solve the system of equations: y = 3x - 4 and 2x - y = 1?

2 Answers
Sep 17, 2015

Answer:

I found:
#x=3#
#y=5#

Explanation:

You can substitute the value of #y# from the first equation into the second and solve for #x# as:
#2x-color(red)([3x-4])=1#
#2x-3x+4=1#
#-x=-3#
#x=3#
substitute back this value into the first equation to find #y#:
#y=3*(3)-4=5#

Answer:

Refer to explanation

Explanation:

We have two equations

#y=3x-4# and #y=2x-1# Multiply the first with 2 and the second with three and substract them

#2y-3y=2*(3x-4)-3(2x-1)=>-y=-5=>y=5# and #x=3#