How do you solve the system of equations #y- 4= 3( x + 2)# and #2x + 6y = 10#?

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Answer 1 · 2016-12-16T13:05:27

#x=-2.5#
#y=2.5#

1) #y-4=3(x+2)#

2) #2x+6y=10#

Solve for #y# in the first equation

#y=3(x+2)+4#
#color(white)y=3x+6+4#
#color(white)y=3x+10#

Substitute it in the second equation

#2x+6(3x+10)=10#
#2x+18x+60=10#
#20x+60=10#
#20x=-50#
#x=-50/20#
#color(white)x=-5/2#
#color(white)x=-2.5#

Substitute #x# in the one of the equations to find #y#

#2(-2.5)+6y=10#
#-5+6y=10#
#6y=15#
#y=15/6#
#color(white)y=5/2#
#color(white)y=2.5#