How do you solve the system of equations #y=-5/3x+1# and #y=-1/3x-3# by graphing?

1 Answer
Jul 9, 2017

The two lines intersect at point #(3, -4)#

Explanation:

Given -

#y=-5/3+1# --------------------- (1)
#y=-1/3-3# ----------------------(2)

To fix a line we need two pieces of information
1) x-intercept and 2) y-intercept
1st equation
At #x=0#

#y=-5/3(0)+1 =1#
So #(0, 1)# is one point

At #y=0#

#-5/3x+1=0#
#-5/3x=-1#
#x=-1xx-3/5=3/5#
#(3/5,0)# is another point

Plot #(0,1) and (3/5,0)#. You get the 1st line.

2nd equation

At #x=0)#

#y=-1/3(0)-3=-3#
#(0,-3)# is one point

At #y=0#

#-1/3x-3=0#
#-1/3=3#
#x=3 xx (-3/1)=-9#
#(-9,0)# is another point
Plot these two points #(0,-3) and (-9,0)#

The two lines intersect at point #(3, -4)#

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