How do you solve the system of equations #y=-6x+18# and #y=3x-9#?

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Answer 1 · 2018-03-26T14:13:24

#x=3 and y=0#

Here,

#y=-6x+18...to(1)#

#y=3x-9....... to (2)#

Comparing #(1) and (2)# for #y#,

#-6x+18=3x-9#

#=>-6x-3x=-18-9#

#=>-9x=-27#

#=>9x=27#

#=>x=3#

Substituting #x=3# in (2), we get

#y=3(3)-9#

#=>y=9-9#

#=>y=0#

Hence,

#x=3 and y=0#