Question

How do you solve the system of equations `y-x=5` and `3y=3x+15`?

Answer 1

The equation has an infinite number of solutions.

Explanation:

These two equations are actually the same equation.

`3y=3x+15" "rarr div 3 rarr y = x+15`

This can be written as `y-x=15` which is the same as the first equation.

If an equation has `2` variables there is no unique solution, but rather an infinite number of possible solutions,

For every value of `x` chosen, there will be a value of `y`.

Possible solution are: `(1,16)" "(2,17)" "(0,15)` etc.

The `y` value is always `15` more than the `x` value.