# How do you solve the system?: x + 3y = –4, 2x + 2y = –8?

Oct 22, 2015

$\left(x , y\right) = \left(- 4 , 0\right)$

#### Explanation:

Given:
[1]$\textcolor{w h i t e}{\text{XXX}} x + 3 y = - 4$
[2]$\textcolor{w h i t e}{\text{XXX}} 2 x + 2 y = - 8$

Multiply [1] by $2$
[3]$\textcolor{w h i t e}{\text{XXX}} 2 x + 6 y = - 8$

Subtract[2] from [3]
[4]$\textcolor{w h i t e}{\text{XXX}} 4 y = 0$

Divide [4] by $4$
[5]$\textcolor{w h i t e}{\text{XXX}} y = 0$

Substitute $0$ for $y$ in [1]
[6]$\textcolor{w h i t e}{\text{XXX}} x + 3 \left(0\right) = - 4$

Simplify
[7]$\textcolor{w h i t e}{\text{XXX}} x = - 4$