How do you solve the system #x+3y=-4# and #2x+6y=5# using substitution?

1 Answer
Oct 16, 2016

Answer:

This systen has no solutions. See explanation for details.

Explanation:

The original system is:

#{(x+3y=-4),(2x+6y=5):}#

To solve it using substitution we have to calculate one of the variables from one equation to substitute it in the other. We can easily calculate #x# from the first equation:

#x=-4-3y#

Now we put the value to the second equation:

#2(-4-3y)+6y=5#

If we try to calculate #y# from this equation we get:

#-8-6y+6y=5#

If we reduce like terms we get:

#-8=5#

This equality is of course false which means that the original system has no solutions.