Question

How do you solve the system `x+3y=-4` and `2x+6y=5` using substitution?

Answer 1

This systen has no solutions. See explanation for details.

Explanation:

The original system is:

`{(x+3y=-4),(2x+6y=5):}`

To solve it using substitution we have to calculate one of the variables from one equation to substitute it in the other. We can easily calculate `x` from the first equation:

`x=-4-3y`

Now we put the value to the second equation:

`2(-4-3y)+6y=5`

If we try to calculate `y` from this equation we get:

`-8-6y+6y=5`

If we reduce like terms we get:

`-8=5`

This equality is of course false which means that the original system has no solutions.