# How do you solve the system x-5y=2 and 9x+8=32y?

Substitute $x = 5 y + 2$ (first equation) into the second to get:
$9 \left(5 y + 2\right) + 8 = 32 y$
$45 y + 18 + 8 = 32 y$
$13 y = - 26$
$y = - 2$
$x = \left(5 \cdot - 2\right) + 2 = - 8$