How do you solve the system $y = 2 x$ $y=2x$ and $x + 3 y = - 14$ $x+3y=-14$ using substitution?

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Answer 1 · 2018-04-21T22:09:38

$(- 2, - 4)$ $(-2, -4)$

Substitute the $2 x$ $2x$ in for $y$ $y$ in the second equation:

$x + 3 (2 x) = - 14$ $x+3(2x)=-14$

$x + 6 x = - 14$ $x+6x=-14$

$7 x = - 14$ $7x=-14$

$x = - 2$ $x=-2$

We know that $x$ $x$ is $- 2$ $-2$ and that $y$ $y$ is $2 \cdot x$ $2*x$ .

$y = 2 \cdot - 2$ $y=2*-2$

$y = - 4$ $y=-4$

$(- 2, - 4)$ $(-2, -4)$

How do you solve the system y=2xy=2x and x+3y=−14x+3y=-14 using substitution?