How do you solve the system #y=3x+8# and #5x+2y=5# using substitution?
1 Answer
Jun 17, 2017
#y=5#
#x=-1#
Explanation:
Given -
#y=3x+8# -------------- (1)
#5x+2y=5# ------------(2)
Substitute
#5x+2(3x+8)=5#
#5x+6x+16=5#
#11x=5-16=-11#
#x=(-11)/11=-1#
#x=-1#
Substitute
#y=3(-1) +8=-3+8=5#
#y=5#
