How do you solve the system $y-4/5x=1$ and $y-x=1$ using substitution?

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Answer 1 · 2018-03-13T18:38:57

$x=0$
$y=1$

$y-x=1|+x$
$y=color(red)(1+x)$

$color(red)(y)-4/5x=1$
$color(red)(1+x)-4/5x=1|-1$
$1/5x=0|*5$
$x=color(blue)(0)$

$y-color(blue)(x)=1|+x$
$y-color(blue)(0)=1$
$y=1$

How do you solve the system y-4/5x=1y-4/5x=1 and y-x=1y-x=1 using substitution?