How do you solve the system #y-4/5x=1# and #y-x=1# using substitution? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Martin C. Mar 13, 2018 #x=0# #y=1# Explanation: #y-x=1|+x# #y=color(red)(1+x)# #color(red)(y)-4/5x=1# #color(red)(1+x)-4/5x=1|-1# #1/5x=0|*5# #x=color(blue)(0)# #y-color(blue)(x)=1|+x# #y-color(blue)(0)=1# #y=1# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1444 views around the world You can reuse this answer Creative Commons License