How do you solve the system $y = 5 x - 2$ $y = 5x − 2$ and $y = 2 x + 10$ $y = 2x + 10$ ?

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How do you solve the system $y = 5 x - 2$ $y = 5x − 2$ and $y = 2 x + 10$ $y = 2x + 10$ ?

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Answer 1 · 2015-05-30T03:17:11

$y = 5 x - 2$ $y = 5x − 2$ .....equation $(1)$ $(1)$
$y = 2 x + 10$ $y = 2x + 10$ .....equation $(2)$ $(2)$

substituting equation $(1)$ $(1)$ in equation $(2)$ $(2)$
$y = 2 x + 10$ $y = 2x + 10$
$5 x - 2 = 2 x + 10$ $5x − 2 = 2x+10$
$3 x = 12$ $3x = 12$
$x = 4$ $x = 4$

substituting the value of $x$ $x$ in equation $(1)$ $(1)$ to find $y$ $y$ :
$y = 5 x - 2$ $y = 5x − 2$
$y = 5 \times 4 - 2$ $y = 5xx4 - 2$
$y = 18$ $y = 18$

the solutions are $x = 4, y = 18$ $color(red)(x = 4 , y = 18$

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How do you solve the system $y = 5 x - 2$ $y = 5x − 2$ and $y = 2 x + 10$ $y = 2x + 10$ ?

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Impact of this question

Science

Math

Humanities

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How do you solve the system y=5x−2y = 5x − 2 and y=2x+10y = 2x + 10?

1 Answer

Related questions

Impact of this question

How do you solve the system $y = 5 x - 2$ $y = 5x − 2$ and $y = 2 x + 10$ $y = 2x + 10$ ?