How do you solve the system $y=6x$ and $2x+3y=-20$ using substitution?

Question

6135 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-25T00:53:43

$2x + 3(6x) = -20$ means $x = -1$ and $y = 6x = -6$ .

We can just plug $y=6x$ into $2x + 3y=-20$ and get

$2x + 3(6x) = -20$

$20 x = -20$

$x = -1$

$y = 6x = -6$

Check:

$-6 = 6 (-1) quad sqrt$

$2 (-1) + 3(-6) = -20 quad sqrt$

How do you solve the system y=6xy=6x and 2x+3y=-202x+3y=-20 using substitution?