How do you solve these equations with the elimination method?

#-4x--y=14# and #3x-9y=-18#

1 Answer
May 17, 2018

#(-36/11,10/11)#

Explanation:

Our equations are as follows:

#-4x+y=14#
#3x-9y=-18#

When we solve equations by elimination, we want to get rid of one variables. The easiest will be #y#.

Let's multiply the first equation by #9#. Thus, our new system is

#-36x+color(blue)(9y)=126#
#3xcolor(blue)(-9y)=-18#

What do you notice? The #y# terms will cancel. We can add these two systems and get

#-33x=108#

Dividing both sides by #-33#, we get

#x=-36/11#

We have solved for one variable, so we can solve for the other. We can plug this in for #x# in the second equation to get

#3(-36/11)-9y=-18#

#=>-108/11-9y=-18#

We can multiply both the #-9y# and the #-18# by #11/11# to achieve a common denominator. We get

#-108/11-99/11y=-198/11#

Adding #-108/11# to both sides, we get

#-99/11y=-90/11#

Let's multiply both sides by #-11# to get

#99y=90#

Dividing both sides by #99#, we get

#y=90/99#

which can be simplified to

#y=10/11#

Thus, the solution of this system is

#(-36/11,10/11)#

Hope this helps!