How do you solve this difficult algebra problem?

F(x)= 2x^2-5x+3 and G(x)=1-4x-x^2

Calculate f(-2) + g(2)

2 Answers
Aug 12, 2018

#10#

Explanation:

#"substitute "x=-2" into" f(x) " and "x=2" into "g(x)#

#f(-2)=2(-2)^2-5(-2)+3#

#color(white)(f-(2))=(2xx4)+(-5xx-2)+3#

#color(white)(f(-2))=8+10+3=21#

#g(2)=1-(4xx2)-(2)^2#

#color(white)(g(2))=1-8-4=-11#

#f(-2)+g(2)=21+(-11)=21-11=10#

Aug 13, 2018

#10#

Explanation:

The key realization is that #f(-2)# means that we will evaluate the function #f# at #x=-2#, and #g(2)# means we evaluate #g# at #x=2#.

Plugging in #-2# for #f#, we get

#f(-2)=2(-2)^2-5(-2)+3=21#

Plugging in #2# for #g#, we get

#g(2)=1-4(2)-(2)^2=1-8-4=-11#

We have been asked to find

#f(-2)+g(2)#, and since we have both values, we can sum them to get

#21-11=10#

Hope this helps!