# How do you solve this physics problem ?

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there are two A and B balls on a pool table at rest, one next to the other. After the impulse, the A-ball moves with an

acceleration of 12 m/s^2 and the B ball with an acceleration of 24 m/s^2. If the angle formed between the two balls is 60°, what will be the distance, in cm, between the two balls after one second, considering that neither of them has fallen into the hole?

THANK YOU

there are two A and B balls on a pool table at rest, one next to the other. After the impulse, the A-ball moves with an

acceleration of 12 m/s^2 and the B ball with an acceleration of 24 m/s^2. If the angle formed between the two balls is 60°, what will be the distance, in cm, between the two balls after one second, considering that neither of them has fallen into the hole?

THANK YOU

##### 1 Answer

#### Answer:

First we find the distance covered by each ball, then the distance between them. They are

#### Explanation:

For both balls, the initial velocity

reduces to:

For Ball A:

For Ball B:

We can't simply subtract one from the other, though, because they are at a

Take the square root of both sides:

We were asked for the answer in

(side note: this is clearly not a standard size pool or billiard table!)