How do you solve this set of linear equations: $198= 6t + 12d; 127= 7t + 6d$ ?

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Answer 1 · 2017-04-23T08:26:10

$color(purple)(t=7,d=13$

$:.6t+12d=198$ --------(1)

$:.7t+6d=127$ ---------(2)

$:. (2) xx 2=14t+12d=254$ -----(3)

$:. (3)-(1)=8t=56$

$:.color(purple)(t=7$

Substitutet=color(purple)7 in (2):

$:.7(color(purple)7)+6d=127$

$:.49+6d=127$

$:.6d=78$

$:.color(purple)(d=13$

Substitute $color(purple)(t=7,d=13$ in (2):

$:.7(color(purple)7)+6(color(purple)13)=127$

$:.49+78=127$

$:.127=127$

How do you solve this set of linear equations: 198= 6t + 12d; 127= 7t + 6d198= 6t + 12d; 127= 7t + 6d?