How do you solve this system of equation: #6x - 3y = 2 and 4x - 5y = 3#?

1 Answer
Nallasivam V
Oct 13, 2017

#y=-5/9#
#x=1/18#

Explanation:

Given _

#6x-3y=2# ---------------------(1)
#4x-5y=3# ---------------------(2)

#6x-3y=2# ---------------------(1) #xx 4#
#4x-5y=3# ---------------------(2)#xx6#

#24x-12y=8# ------------- (3)
#24x-30y=18# ---------------(4) -- #(3) - (4)#

#18y=-10#
#y=-10/18=-5/9#

Substitute #y=-5/9# in equation (1)

#6x-3(-5/9)=2#

#6x+5/3=2#
#6x=2-5/3=(6-5)/3=1/3#

#x=1/3 xx1/6=1/18#

#y=-5/9#
#x=1/18#

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