How do you solve this system of equation: #x+ 2y = 10 and 2x + 4y = 32#?
1 Answer
Oct 16, 2017
See explanation.
Explanation:
The original system is:
#{(x+2y=10),(2x+4y=32):} #
If we divide the second equation by
#{(x+2y=10),(x+2y=16):} #
If we subtract the first equation from the second we get an equality:
#0=6#
The final equality means that the system of equations is inconsistent and therfore has no solutions.
