How do you solve this system of equations: #-2x - y = 11 and - 2x - 9y = 3#?

1 Answer
Dec 3, 2017

#x = - 6#
#y = 1#

Explanation:

Solve both equations for #-2x# and set them equal to each other.

#−2x−y=11#
so #-2x = 11 + y#

#−2x−9y=3#
so #-2x = 3 + 9y#

Because both of the equations are equal to #-2x,# they are equal ro each other.

#11 + y = - 2x#   and   #-2x= 3 + 9y#

#11 + y = 3 + 9y#

1) Subtract #y# from both sides to get all the #y#'s together

#11 = 3 + 8y#

2) Subtract 3 from both sides to isolate the #8y# term

#8 = 8y#

3) Divide both sides by 8 to isolate #y#
#1 = y# #larr# answer for #y#
~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

To find #x#, sub in #1# for #y# and solve for #x#

#−2x−y=11#
#- 2x - 1 = 11#

1) Add 1 to both sides to isolate the #- 2x# term
#- 2x = 12#

2) Divide both sides by #- 2# to isolate #x#
#x = - 6# #larr# answer for x

Answer:
#x = - 6#
#y = 1#
~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

Check
Sub in the values for #x# and #y# back into the original equations.

(1) #−2x−9y=3#

#(-2)(-6) - (9)(1)# is supposed to equal #3#

#12 -9# is supposed to equal #3#

#3# does equal #3#   ✓
..................................

(2) #−2x−y=11#

#(-2)(-6) - 1# is supposed to equal #11#

#12 - 1# is supposed to equal #11#

#11# does equal #11#   ✓