How do you solve this system of equations: #-3x - 5y = 4;- 5x - 4y = 24#?

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Answer 1 · 2018-04-25T02:34:57

#x=-8#, and #y=4#.

Equation 1

#-3x-5y=4#

Equation 2

#-5x-4y=24#

I'm going to solve this by substitution.

First solve Equation 1 for x.

Equation 3

#x=-(5y+4)/3#

Next, substitute this expression for #x# into Equation 2

Equation 4

#(5(5y+4))/3-4y=24#

Now solve for #y#.

#25y+20-12y=72#

#13y=52#

#y=4#

Now put this value for #y# into Equation 3 to determine #x#.

#x=-(5(4)+4)/3=-8#