How do you solve this system of equations: #5p = - 6q + 25; 3p - 4q = - 13#?

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Answer 1 · 2018-07-12T08:27:30

#p=11/19,q=70/19#

Dividing the first equation by #5#

#p=-6/5q+5#

substituting this in the second equation

#3(-6/5q+5)-4q=-13#
expanding

#-18/5q-4q+15=-13#
adding #-15#
so we get

#-18/5q-20/5q=-28 #

so we get

#-38q=-140#

so #q=70/19#

#p=-6/5*70/19+5=11/19#