How do you solve this system of equations : #6x + 3y = 27 ; - 4x + 7y = 27#?

1 Answer
Sep 12, 2017

#x = 2, y= 5#

Explanation:

Hi there!

#6x + 3y = 27#
#-4x + 7y = 27#

We need to solve #6x + 3y = 27# for #x#
#6x = 27 - 3y#
Divide both sides by 6
#(6x)/6 = (27 - 3y)/6#
#x =(-1)/2 y + 9/2#
Now we need to substitute #(-1)/2 y + 9/2# for #x# in #-4x+7y=27#
#-4x + 7y = 27#
#-4(-1/2 y +9/2) + 7y = 27#
Simplify both sides
#9y - 18 = 27#
#9y = 27 + 18#
#9y = 45#
Divide both sides by #9#
#(9y)/9 = 45/9#
#y = 5#
Substitute #5# for #y# in #x = (-1)/2 y + 9/2#
#x = (-1)/2 y + 9/2#
#x = (-1)/2 (5) + 9/2#
Simplify
#x = 2#

Final answer : #x = 2# and #y=5#

I hope I helped!