How do you solve this system of equations :#x+ 5y = 4;5x + 3y = - 2#?

Question

458 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-24T04:28:30

#x=-1#
#y=1#

Given -

#x+5y=4# ------------------ (1)
#5x+3y=-2# -------------- (2)

Solve equation (1) for #x#

#x=4-5y#

Substitute #x=4-5y# in equation (2)

#5(4-5y)+3y=-2#

#20-25y+3y=-2#
#-22y=-2-20#
#y=(-22)/(-22)=1#
#y=1#

Substitute #y=1# in equation (1)

#x+5(1)=4#
#x+5=4#
#x=4-5=-1#
#x=-1#