Question

How do you solve `|x+1|≤8`?

Answer 1

`-9<=x<=7`

Explanation:

Since

`|f(x)|<=kharr -k<=f(x)<=k`,

you have, in this case:

`|x+1|<=8 harr -8<=x+1<=8`

`-8-1<=x<=8-1`

`-9<=x<=7`