How do you solve #|x ^ { 2} - 1| = 0#?

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Answer 1 · 2016-12-29T16:23:21

#x = 1# or #x = -1#

Because this equation contains an absolute value function it is a special case.

But it has one more special case - the absolute value term is equated to #0# therefore we only need to solve this for one term #0#:

#x^2 - 1 = 0#

#x^2 -1 + 1 = 0 + 1#

#x^2 - 0 = 1#

#x^2 = 1#

#sqrt(x^2) = +-sqrt(1)#

#x = +-(1)#

#x = 1# or #x = -1#