How do you solve $x^{2} + 1.4 x = 1.2$ $x^2+1.4x=1.2$ by completing the square?

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Answer 1 · 2016-12-27T19:06:18

$x = - 0.6 or x = - 2$ $x=-0.6 or x=-2$

$x^{2} + 1.4 x = 1.2$ $x^2+1.4x=1.2$

$(x^{2} + 1.4 x - 1.2 = 0$ $(x^2+1.4x-1.2=0$

$(x - 0.6) (x + 2)$ $(x-0.6)(x+2)$

$x - 0.6 = 0$ $x-0.6=0$

$x = 0.6$ $x=0.6$

$x + 2 = 0$ $x+2=0$

$x = - 2$ $x=-2$

How do you solve x2+1.4x=1.2x^2+1.4x=1.2 by completing the square?