How do you solve #x^ { 2} + 10x + 32= - 2x - 4#?

1 Answer
EET-AP
Oct 13, 2017

To solve #x^2+10x+32=-2x-4# you need to subtract #-2x-4# from both sides of the equation and then unFOIL the result.
#x^2+10x+32=-2x-4to# then #x=-6#

Explanation:

#x^2+10x+32=-2x-4#

#x^2+10x+32-(-2x-4)=cancel(-2x)cancel(-4)-cancel((-2x-4))=0#

#x^2+12x+36=0#

#(x+ 6)(x+6)=0#

#x-6=0# and #x=-6#

Related questions
Impact of this question
1082 views around the world
You can reuse this answer
Creative Commons License