# How do you solve x^ { 2} + 10x + 32= - 2x - 4?

Oct 13, 2017

To solve ${x}^{2} + 10 x + 32 = - 2 x - 4$ you need to subtract $- 2 x - 4$ from both sides of the equation and then unFOIL the result.
${x}^{2} + 10 x + 32 = - 2 x - 4 \to$ then $x = - 6$

#### Explanation:

${x}^{2} + 10 x + 32 = - 2 x - 4$

${x}^{2} + 10 x + 32 - \left(- 2 x - 4\right) = \cancel{- 2 x} \cancel{- 4} - \cancel{\left(- 2 x - 4\right)} = 0$

${x}^{2} + 12 x + 36 = 0$

$\left(x + 6\right) \left(x + 6\right) = 0$

$x - 6 = 0$ and $x = - 6$