How do you solve #x^ { 2} - 14x + 25= 0#?

1 Answer
marfre
Apr 18, 2017

#x = 7 +- 2 sqrt(6)#

Explanation:

Since this equation doesn't factor in a simple way you need to use the quadratic formula.

Quadratic formula in general form is #Ax^2 + Bx + C = 0#

Use the quadratic formula #x = (-B +- sqrt(B^2 - 4AC))/(2A)#

#x = (14 +- sqrt(196 - 4*25))/2 = 7 +- sqrt(96)/2 = 7+- sqrt(16*6)/2#

#x = 7 +- (4sqrt(6))/2 = 7 +- 2 sqrt(6)#

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