How do you solve #x^2 + 30 = 24#?

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Answer 1 · 2018-07-24T12:17:35

#x=\pmi\sqrt6#

Given quadratic equation will have two roots as follows

#x^2+30=24#

#x^2=24-30#

#x^2=-6#

#x=\pm\sqrt{-6}#

#=\pm \sqrt{6i^2}#

#=\pmi\sqrt6#