# How do you solve x^ { 2} + 3x - 6.75= 0?

$x = \frac{3}{2} , - \frac{9}{2}$

#### Explanation:

Probably the easiest way to go would be using the quadratic formula:

$x = \frac{- b \setminus \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

We have $a = 1 , b = - 3 , c = - 6.75$

$x = \frac{- 3 \setminus \pm \sqrt{{\left(3\right)}^{2} - 4 \left(1\right) \left(- 6.75\right)}}{2 \left(1\right)}$

$x = \frac{- 3 \setminus \pm \sqrt{9 + 27}}{2}$

$x = \frac{- 3 \setminus \pm \sqrt{36}}{2}$

$x = \frac{- 3 \setminus \pm 6}{2}$

$x = \frac{3}{2} , - \frac{9}{2}$

Which we can see here on the graph:

graph{x^2+3x-6.75}