Question

How do you solve `x^ { 2} = ( 3x - 7) ^ { 2} + ( 5x + 7)`?

Answer 1

`x !in RR`

Explanation:

[0]`x²=(3x-7)²+(5x+7)`
[1]`x²=9x²-42x+49+5x+7`
[2]`x²=9x²-37x+56`
[3]`8x²-37x+56=0`
[4]`Delta=(-37)²-4*8*56`
[5]`Delta=-423`
We can see that our Delta is not a positive number, so there's no solutions in `RR` ( but there's in `CC`. )
\0/ here's our answer !