# How do you solve x^2-4x+5=0 by completing the square?

May 15, 2018

No solutions.

#### Explanation:

${x}^{2} - 4 x = - 5$

${\left(x - 2\right)}^{2} - 4 = - 5$

${\left(x - 2\right)}^{2} = - 1$

$\left(x - 2\right) = \pm \sqrt{- 1}$

cannot do the square root of a negative number so no solutions