How do you solve #x^ { 2} + 5x - 17= 10x - 3#?
1 Answer
Aug 23, 2017
Explanation:
#"collect terms on left side and equate to zero"#
#rArrx^2-5x-14=0#
#"the product of the factors of - 14 which sum to - 5"#
#"are - 7 and +2"#
#rArr(x-7)(x+2)=0#
#"equate each factor to zero and solve for x"#
#x-7=0rArrx=7#
#x+2=0rArrx=-2#
#"solutions are "x=-2" or "x=7#
