How do you solve #x^ { 2} + 5x - 17= 10x - 3#?

1 Answer
Jim G.
Aug 23, 2017

#x=-2" or "x=7#

Explanation:

#"collect terms on left side and equate to zero"#

#rArrx^2-5x-14=0#

#"the product of the factors of - 14 which sum to - 5"#
#"are - 7 and +2"#

#rArr(x-7)(x+2)=0#

#"equate each factor to zero and solve for x"#

#x-7=0rArrx=7#

#x+2=0rArrx=-2#

#"solutions are "x=-2" or "x=7#

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