How do you solve #x^2-6=x# using the quadratic formula?

1 Answer
devi f.
Mar 2, 2018

You do the math, I will show the method.

Explanation:

Rewrite the equation by reansposing the RHS to the LHS:
#x^2 -x -6 = 0#

This is quadratic equation of form:
#ax^2 +bx +c =0#

with solution:
#x= (-b +- sqrt(b^2-4ac))/(2a)#

So you have
#a=1#
#b=-1#
#c=-6#

Substitute values in above and get the answer

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