Question

How do you solve `-x + 2= 6x - 3`?

Answer 1

See a solution process below:

Explanation:

Add `color(red)(x)` and `color(blue)(3)` to each side of the equation to isolate the `x` term while keeping the equation balanced:

`color(red)(x) - x + 2 + color(blue)(3) = color(red)(x) + 6x - 3 + color(blue)(3)`

`0 + 5 = color(red)(1x) + 6x - 0`

`5 = (color(red)(1) + 6)x`

`5 = 7x`

Now, divide each side of the equation by `color(red)(7)` to solve for `x` while keeping the equation balanced:

`5/color(red)(7) = (7x)/color(red)(7)`

`5/7 = (color(red)(cancel(color(black)(7)))x)/cancel(color(red)(7))`

`5/7 = x`

`x = 5/7`